How do you solve a triangle given a = 8, c = 12, and B = 72?

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How do you solve a triangle given a = 8, c = 12, and B = 72?

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Answer 1 · 2015-11-08T19:20:03

Law of sine and cosine

Explanation:

You first need to fine the missing side, in this case it would be 'b.'

Use this equation: $b^{2} = a^{2} + c^{2} - 2 a c sin b$ $b^2=a^2+c^2-2acsinb$

You will have the side b and can use the the same equation, just manipulated to find the other angle.

That equation is: $\frac{- a^{2} + b^{2} + c^{2}}{2 b c} = sin A$ $(-a^2+b^2+c^2)/(2bc)=sinA$

That will give you the angle of angle A. Since you have 2 angles of the triangle you can easily find the third, simply subtracting the sum of both angles from 180.

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How do you solve a triangle given a = 8, c = 12, and B = 72?

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