Question

How do you evaluate 5 radical 16/3 - radical 9/2?

Answer 1

`20/sqrt(3)-3/sqrt(2)`

Explanation:

You have that `sqrt(a/b)=sqrt(a)/sqrt(b)`. So,

`sqrt(16/3) = sqrt(16)/sqrt(3) = 4/sqrt(3)`.

Also,

`sqrt(9/2)=sqrt(9)/sqrt(2) = 3/sqrt(2)`

Now that we have simplified the radicals, we can write the whole expression:

`5*4/sqrt(3) - 3/sqrt(2) = 20/sqrt(3)-3/sqrt(2)`