A compound with empirical formula CH was found by experiment to have a molar mass of approximately 91. What is the molecular formula of the compound?

1 Answer
anor277
Nov 9, 2015

The molecular formula is always a multiple of the empirical formula.

Explanation:

So, #MF = n*(EF)#, where #MF, EF# are the molecular and empirical formulae respectively.

Thus, #91*g*mol^-1= nxx(12 + 1)*g*mol^-1#.

Or #n=91/13#; so #n# #=# #7#? Please report the molecular formula back here.

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