How do you evaluate #log_3 81 #? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer Katie Lau Nov 11, 2015 The answer is #4#. Explanation: #log_(3)81# is the same thing as writing #3^x = 81#, where you have to solve for #x#. #3# is the base number. #3 * 3 * 3 * 3# is #81#, proving #3^4 = 81#. So, #4# is the answer. Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 19456 views around the world You can reuse this answer Creative Commons License