Question

How do you graph using slope and intercept of `-7x-2y= -5`?

Answer 1

Plotting y-intercept= `5/2` and drawing 16 degrees angle towards positive x-axis.

Explanation:

Let's write the given equation in y = mx +c form
y = -`7/2`x + `5/2`
here the y intercept = `5/2`
Slope = -`7/2`x
graph{-7x-2y = -5 [-10, 10, -5, 5]}
Mark at 2.5 to mark the y-intercept. Since the slope is -7/2. `tan^-1` (7/2) = 74.04 degrees. Negative value of `tan^-1` (-7/2) = (180 - 76)= 106. Interior angle at 2.5 will be 16 degrees. Draw 16 degrees from 2.5 intercept. The line which passes through x-axis will be the required equation.