Question

What is the value of the hypotenuse of an isosceles triangle with a perimeter equal to `16 + 16sqrt2`?

Answer 1

16

Explanation:

That triangle is half a square. `(t, t, t sqrt 2)`

`2p = t + t + t sqrt2 = 16 + 16sqrt 2`

`t = 16 cdot (1 + sqrt 2)/(2 + sqrt 2)` // times `sqrt 2`

Hypotenuse = `t sqrt 2 = 16 cdot (sqrt 2 + 2)/(2 + sqrt 2)`