What are the equations of 2 lines that are perpendicular to the line: #4x+y-2 = 0#?

1 Answer
Nov 15, 2015

#y = 1/4 x + b#

(#b# can be any number)

Explanation:

Lets rewrite the equation #4x+y-2=0# to solve for y.

#4x+y-2=0#
#4x+y=2#
#y=-4x+2#

This new equation now fits into the helpful format #y=mx+b#

With this formula #b# is equal to the y intercept and #m# is equal to the slope.

So if our slope is #-4# then to calculate a perpendicular line we flip the number and change the sign. So #-4/1# becomes #1/4#.

We can now construct a new equation with the new slope:

#y =1/4 x +2#

That is a perfectly acceptable answer to this question, and to easily generate more equations we can simply change the y intercept to any number we want.

#y =1/4 x +2#
#y =1/4 x +10#
#y =1/4 x - 6#