Question

How do you find `int 1-tan^2xdx`?

Answer 1

Use trigonometric identity: `tan^2x = sec^2x-1` to rewrite.

Explanation:

`int (1-tan^2x)dx = int(1-(sec^2x-1))dx`

`= int(2-sec^2x) dx`

`= 2x-tanx +C`