How do you verify #tan(theta)/cot(theta)=tan^2(theta)#?

1 Answer
Nov 15, 2015

Use the definition of #cot(theta)# as the inverse of #tan(theta)#
and the fact that dividing by #1/x# is the same as multiplying by #x#

Explanation:

#(tan(theta))/(cot(theta))#

#color(white)("XXX")=tan(theta) div cot(theta)#

#color(white)("XXX")=tan(theta) div 1/(tan(theta)) # [by definition of #cot(theta)#]

#color(white)("XXX")=tan(theta)xxtan(theta) # [since #axx1/x <=> axxx#]

#color(white)("XXX")=tan^2(theta)#