What is the equation of the line passing through (11,17) and (23,11)?

2 Answers
Nov 18, 2015

x+2y=45

Explanation:

1st point=(x_1, y_1)=(11, 17)
2nd point=(x_2, y_2)=(23, 11)

First, we will have to find the slope m of this line:

m=(y_2-y_1)/(x_2-x_1)=(11-17)/(23-11)=-6/12=-1/2

Now, use point-slope formula with one of the given points:
y-y_1=m(x-x_1)
y-17=-1/2(x-11)
y-17=-1/2x+11/2
y=-1/2x+11/2+17
y=(-x+11+34)/2
2y=-x+45
x+2y=45

Nov 18, 2015

y = -x/2 + 45/2

Explanation:

Usung the formula y-y_1 = m(x-x_1)
Considering
(11, 17) and (23, 11)
(x_1, y_1) and (x_2, y_2)

m (gradient) = (y_2-y_1)/(x_2-x_1)

m = (11-17)/(23-11)

m = -6/12

m = -1/2

y-17 = -1/2(x-11)
y-17 = -x/2+11/2
y = -x/2+11/2+17
y = -x/2 + 45/2

This is the equation of the line