How do you factor the trinomial 18a^2+48a+32?
1 Answer
Nov 18, 2015
Explanation:
- First reduce it to the smallest terms
- They are all divisible by 2
16(last term) x 9(co-efficient of
-
Think of two numbers that
rArr When you multiply them = 144
rArr When you add them = 24 (co-efficient ofa ) -
12 and 12
rArr 12 x 12 = 144
rArr 12 + 12 = 24 -
Replace the middle number with 12 and 12
9a^2 + 12a + 12a + 16 -
Split the expression
9a^2 + 12a----- | ----- + 12a + 16 -
Factorise the two
3a(3a + 4) + 4(3a +4) -
Common factors so group
(3a + 4)(3a +4)
- Remember we divided by 2
rArr 2(3a+4)^2