A balloon has a volume of 253.2 mL at 356 K. The volume of the balloon is decreased to 165.4 mL. What is the new temperature?

1 Answer
Nov 19, 2015

The new temperature is #"233 K"#.

Explanation:

Charles' law states that when pressure is held constant, temperature and volume are directly proportional. The equation to use is #V_1/T_1V_2/T_2#.

Given
#V_1=252.3cancel"mL"xx(1"L")/(1000cancel"mL")="0.2523 L"#
#T_1="356 K"#
#V_2=165.4cancel"mL"xx(1"L")/(1000cancel"mL")="0.1654 L"#

Unknown
#T_2#

Equation
#V_1/T_1V_2/T_2#

Solution
Rearrange the equation to isolate #T_2#.
#T_2=(T_1V_2)/V_1#

#T_2=((356"K")xx(0.1654cancel"L"))/(0.2523cancel"L")="233 K"#