Question

How do you factor completely `45x^3+93x^2+30x`?

Answer 1

Take out the common factor of 3x and then factor the quadratic as normal

Explanation:

`45x^3 +93x^2 +30x` = `3x (15x^2 + 31x + 10)`
`3x(15x^2 +31x +10)` = `3x(5x + 2)(3x + 5)`