Question

How do you find the derivative of `f(x)=x^3 - 5x^2 - 4x + 20`?

Answer 1

`3x^2-10x-4`

Explanation:

Differentiate each part separately!
Remember standard method `d/dx (x^n) = nx^(n-1)`

`(dy)/dx = d/dx(x^3) -d/dx(5x^2)-d/dx(4x) +d/dx(20)`

`(dy)/dx = 3x^2 - 10x-4+0`