What are the intercepts of $2y-x=1$ ?

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Answer 1 · 2015-11-19T15:47:40

$"x-intercept" -> (-1,0)_("y=0")$

$"y-intercept" -> (0,1/2)_("x=0")$

Given: $2y-x=1$

$2y =x+1$

$y=1/2x+1/2$

Tont B

At $x=0 , y= 1/2$

At $y=0, x=-1$

So

$"x-intercept" -> (-1,0)_("y=0")$

$"y-intercept" -> (0,1/2)_("x=0")$

What are the intercepts of 2y-x=12y-x=1?