What is the equation of a line that satisfies the given conditions: perpendicular to #y= -2x + 5# and passing through (4, -10)?

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Answer 1 · 2015-11-19T16:41:19

#y=0.5x-12#

Since the line must be perpendicular, the slope #m# should be the opposite and inverse of the one in your original function.

#m=-(-1/2)=1/2=0.5#

Now all you have to do is use the point slope equation:

Given coordinate: #(4,-10)#

#y-y_0=m(x-x_0)#

#y-(-10)=0.5(x-4)#

#y+10=0.5x-2#

#y=0.5x-2-10#

#y=0.5x-12#