How do you simplify #(x^2+x+15)/(x^2-3x)#?

1 Answer
Nov 19, 2015

#( 15)/( - 4x )#

Explanation:

When you see this equation:
#(x^2 + x + 15)/(x^2 - 3x)#

What you need to remember is that you see a #x^2# on both sides of the fraction-line. This means you can cross them out, because they are equal on both sides.

So now your equation looks like this:
#( x + 15)/( - 3x)#

Now as you can see, both sides of the fraction-line have a #x#. So what you do is you take the smallest #x# of the largest #x#, so that you can remove the #x#

In this case, the smallest #x# is the #x# on the numerator and the biggest #x# is the #- 3x# on the denominator.

If you apply what I just said, your equation would be:
#( x - x + 15)/( - 3x - x) = ( 15)/( - 4x )#

So the simplified version of #(x^2 + x + 15)/(x^2 - 3x) = ( 15)/( - 4x )#