What is the standard form of #y= (x^2-1)(3x-1) + (x+1)^2#? Algebra Polynomials and Factoring Polynomials in Standard Form 1 Answer Tony B Nov 20, 2015 #y=3x^3-x+2# Explanation: Given #(color(blue)(x^2-1))(3x-1) + (color(red)(x+1))(x+1)# #y= color(blue)(x^2)(3x-1) color(blue)(-1)(3x-1)color(red)(+x)(x+1)color(red)(+1)(x+1)# #y=(3x^3-x^2)+(-3x+1)+(x^2+x)+(x+1)# Collecting like terms #y= 3x^3 +(-x^2+x^2)+(-3x+x+x)+(1+1)# #y=3x^2+0-x+2# #y=3x^3-x+2# Answer link Related questions What is a Polynomial? How do you rewrite a polynomial in standard form? How do you determine the degree of a polynomial? What is a coefficient of a term? Is #x^2+3x^{\frac{1}{2}}# a polynomial? How do you express #-16+5f^8-7f^3# in standard form? What is the degree of #16x^2y^3-3xy^5-2x^3y^2+2xy-7x^2y^3+2x^3y^2#? What is the degree of the polynomial #x^4-3x^3y^2+8x-12#? What is the difference between a monomial, binomial and polynomial? How do you write #y = 2/3x + 5# in standard form? See all questions in Polynomials in Standard Form Impact of this question 1380 views around the world You can reuse this answer Creative Commons License