How do you simplify #sqrt(-24) / sqrt(-2)#? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer mason m Nov 22, 2015 #2sqrt3# Explanation: Know that: #sqrta/sqrtb=sqrt(a/b)# #sqrt(a^2*b)=asqrtb# #sqrt(-24)/sqrt(-2)=sqrt((-24)/-2)=sqrt12=sqrt(2^2*3)=2sqrt3# Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 2074 views around the world You can reuse this answer Creative Commons License