Given: A line segment AC with AB=BC Prove: 1/2AC=BC? Geometry Geometric Constructions Constructing Bisectors of Lines and Angles 1 Answer Konstantinos Michailidis Nov 23, 2015 Hence #AB=BC# we have that #AC=AB+BC=BC+BC=>AC=2*BC=>BC=1/2*AC# Answer link Related questions In a triangle #DeltaABC#, #AB# and #AC# are extended and bisectors of exterior angles are drawn... See all questions in Constructing Bisectors of Lines and Angles Impact of this question 3624 views around the world You can reuse this answer Creative Commons License