How do you solve #Log_(5)x=3#?

1 Answer
Nov 24, 2015

I found: #x=125#

Explanation:

You can use the definition of logarithm that basically tells you that you take the base, #5#, to the right pushing up the #3# that becomes an exponent and, in doing so, lose the log:
#cancel(log)x=color(red)(5^3)#
or
#x=5^3=125#