Question

How do you solve `Log_(5)x=3`?

Answer 1

I found: `x=125`

Explanation:

You can use the definition of logarithm that basically tells you that you take the base, `5`, to the right pushing up the `3` that becomes an exponent and, in doing so, lose the log:
`cancel(log)x=color(red)(5^3)`
or
`x=5^3=125`