How do you find the x and y intercepts for #13 x-20 y= 17#?

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Answer 1 · 2015-11-26T16:24:42

x-intercept is #(17/13, 0)#
y-intercept is #(0, -17/20)#

To solve for x-intercept, we let y= 0

#13x -20(0)= 17#

#(13x)/13 = 17/13#

#x= 17/13 => (17/13, 0)#

To solve for y-intercept, let x= 0

#13(0) -20 y = 17#

#(-20y)/-20 = 17/(-20)#

#y = -17/20 => (0, -17/20)#