I'm taking a wild guess here that with #x#, you actually meant "x", the multiplication sign.
I'm also taking a second wild guess that "#cos b#" on your left side should have been a part of the denominator...
So, I think what you would like to prove is
#sin(a-b) / (sin a * cos b ) = 1 - cot a * tan b #
To prove this, let's use the following:
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#cot x = cos x / sin x #
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#tan x = sin x / cos x #
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#sin (x - y ) = sin x cos y - cos x sin y #
Now you can prove the identity as follows:
#sin(a-b) / (sin a * cos b ) = (sin a cos b - cos a sin b) / (sin a cos b) #
# color(white)(xxxxxxxx) = (sin a cos b) / (sin a cos b) - (cos a sin b) / (sin a cos b) #
# color(white)(xxxxxxxx) = 1 - (cos a * sin b) / (sin a * cos b) #
# color(white)(xxxxxxxx) = 1 - cos a / sin a * sin b / cos b #
# color(white)(xxxxxxxx) = 1 - cot a * tan b #
Hope that this helped.