Question

How do you convert `r= 8(cos(x)+(sin(x))` into cartesian form?

Answer 1

`x^2+y^2 = 8(x+y)`

Explanation:

Multiply both sides by `r`:

`r^2 = 8(rcos(x)+rsin(x))`

Since `r=sqrt(x^2+y^2)`, then `r^2=x^2+y^2`. On the other hand, you have that

`x=rcos(x)`
`y=rsin(x)`.

Plug all these three into the equation and get

`x^2+y^2 = 8(x+y)`