How do you simplify #139!#?

1 Answer
mason m
Nov 27, 2015

#96157231969410890041971956135297253988256079629956908500367081914696145479218112119985149618783441690577636407442564169301886059792163365100096999581219760002673769583579570682891939608962934200435638009856000000000000000000000000000000000#

Explanation:

Any number with the factorial sign (#!#), can be written as the product of all the integers less than or equal to the number.

#6! =6xx5xx4xx3xx2xx1=720#

Thus, #139! = 139xx138xx137xx136xx...xx3xx2xx1#.

Related questions
See all questions in Factorial Identities
Impact of this question
1662 views around the world
You can reuse this answer
Creative Commons License