Question

A pendulum on earth with a length of 1.2 m and a mass .25 kg is set in motion. What is its period?

Answer 1

I found `T=2.2` seconds

Explanation:

The period `T` of the pendulum depends on the length `l` and acceleration of gravity `g` as:
`T=2pisqrt(l/g)`
so:
`T=2pisqrt(1.2/9.8)=2.19~~2.2` seconds