What are the asymptote(s) and hole(s), if any, of f(x)= (x+3)/(x^2-9)?
1 Answer
Hole at
Vertical asymptote:
Horizontal asymptote:
Explanation:
Given
Step 1: Factor the denominator, because it's a difference of square
Because the function reduce to equivalent form , we have a hole on the graph at
y_(value)= f(-3)= 1/(-3-3) hArr f(-3) = -1/6
Hole atcolor(red)((-3, -1/6)
Vertical asymptote: Set denominator equal to zero
x-3= 0 hArr x= 3
Vertical asymptote :
Horizontal asymptote:
Because the degree of the numerator is LESS than the degree of the denominator, the horizontal asymptote is