How do you solve #2(n+1)+1=(n-5)+(n+2)#?

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Answer 1 · 2015-12-01T17:32:52

No solution.

Distribute the 2 to the terms in the parentheses:

#2(n+1) = 2n+2#.

Now you have #2n+2+1=n−5+n+2#.

Combine like terms and you're left with #2n+3=2n-3#.

Isolate terms with variable #n# to one side (take opposite sign):

#2n-2n=-3+3#

#0n=0#

So no solution.