Question

How do you find the roots, real and imaginary, of `y=-2x^2 + 7x +6` using the quadratic formula?

Answer 1

Plug in a, b, c in the quadratic equation which is `((-b)+-sqrt(b^2-4ac))/(2a)`

`a=`coefficient of `x^2`.
`a=-2`

`b=` coefficient of `x`.
`b=7`

`c=` the constant in the equation.
`c=6`

`((-7)+-sqrt((7)^2-4(-2)(6)))/(2(-2))`