How do you solve the following linear system: #x-6y= 7 , 5x+2y=10 #?

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Answer 1 · 2015-12-02T20:03:12

#x=37/16#, #y=-25/32#

From the first equation, you have that #x=6y+7#. Substitute this expression for #x# in the second equation to have

#5(6y+7)+2y=10#

#30y+35+2y=10#

#32y = -25#

#y=-25/32#

Once #y# is known, you can get #x# from

#x=6y+7 = 6*(-25/32)+7 = 37/16#