How do you find the equation for a circle with center is (-2,-3) and radius 3?

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Answer 1 · 2015-12-02T21:01:38

The equation for a circle with centre #(h, k)# and radius #r# can be written in standard form as:

#(x-h)^2+(y-k)^2 = r^2#

In our case:

#(x+2)^2+(y+3)^2 = 9#

A standard form for the equation of a circle of radius #r# and centre #(h, k)# is:

#(x-h)^2+(y-k)^2 = r^2#

In our case #h=-2#, #k=-3# and #r=3#, so:

#(x-(-2))^2 + (y-(-3))^2 = 3^2#

or more simply:

#(x+2)^2+(y+3)^2=9#