Is #f(x) = -3x^4+x^3 - 4x^2+x-4# concave or convex at #x=11#?

1 Answer
Dec 3, 2015

The answer lies in the sign of the second derivative: the function is convex if the second derivative is positive, and concave otherwise. So, let's compute it.

#f'(x) = -12x^3+3x^2-8x+1#

#f''(x) = -36x^2+6x-8#

Now evaluate #f''(11)#:

#f''(11)=-36*(11^2) + 6*11 - 8 = -36*121 +66-8#, which is clearly negative (it's #-4298# to be precise), so the function is concave in that point.