What are the intercepts of #-y+3x=1#?

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Answer 1 · 2015-12-03T19:15:44

Plug in #0# for #x# or #y# to find that the #y# intercept is at #(0, -1)# and the #x# intercept is at #(1/3, 0)#

The #x# and #y# intercepts occur when #y=0# and #x=0#, respectively.

When #x=0# we have

#-y + 3(0) = 1 => y = -1#

Thus the #y# intercept is at #(0, -1)#.

When #y=0# we have

#-(0) + 3x = 1 => x = 1/3#

Thus the #x# intercept is at #(1/3, 0)#