A stone is thrown with a horizontal velocity of 30.0 m/s from the top of a cliff 80.0 m high. How long will it take to strike the level ground at the base of the cliff, and how far from the foot of the cliff will it strike?
1 Answer
Dec 3, 2015
(a)
(b)
Explanation:
(a)
Taking the vertical component of motion we can assume that the initial velocity is zero so:
(b)
The horizontal component of velocity is constant so:
Distance = speed x time