Question

How do you solve `ln(7x+6)=1`?

Answer 1

I found: `x=(e-6)/7`

Explanation:

You can use the definition of log remembering that the base of `ln` is the irrational number `e`:
`ln(7x+6)=1`
`7x+6=e^1`
rearranging:
`x=(e-6)/7`