How do you factor #y= x^4 + 5x^2 - 6# ?
2 Answers
Explanation:
Given
We notice that all terms containing the variable
so to simplify things initially we will replace
which can easily be factored as:
Restoring
The first factor,
but the second,
giving
Explanation:
Perhaps it will help if I rewrite this expression for
Let
This is something we can factor pretty easily.
Just substitute back to get
And now, the last step is to factor the second bit which is a difference of two squares: