If chlorine gas has a volume of 465mL at 50°C ,what is the volume if the temperature decreases to 30°C?

1 Answer
Dec 6, 2015

#V_2=436mL#

Explanation:

To answer this question, we will need to assume the following:

  1. Chlorine gas is behaving ideally, so we can use the ideal gas law: #PV=nRT#
  2. During the process, the pressure is remaining constant.

Since we are heating the ballon, the number of mole is not changing and therefore, #n# is constant too.

Thus #V=underbrace((nR)/P)_(color(blue)("constant k"))T=>V/T=k=>(V_1)/(T_1)=(V_2)/(T_2)#

#=>V_2=(V_1)/(T_1)xxT_2=(465mL)/(323cancel(K))xx303cancel(K)=436mL#

Therefore, chlorine will occupy a volume of #436mL# at #30^@C#.