Question

How do you find the cartesian graph of `r cos(θ) = 9`?

Answer 1

`x=9`

Explanation:

`cos(theta) = (x_theta)/(sqrt((x_theta)^2+(y_theta)^2))`

`r= sqrt((x_theta)^2+(y_theta)^2))`

Therefore
`color(white)("XXX")rcos(theta) = cancel(sqrt((x_theta)^2+(y_theta)^2))xx (x_theta)/(cancel(sqrt((x_theta)^2+(y_theta)^2))`

and since `r*cos(theta) = 9`

`color(white)("XXX")x_theta = 9`