Question

How do you solve `-log x = 4.176`?

Answer 1

`x~= 6.668xx10^(-5)`

Explanation:

`-log x = 4.176`
`color(white)("XXX") rArr log x = -4.176`

`color(white)("XXX")10^(-4.176) = x`

therefore (using a calculator)
`color(white)("XXX")x = 6.668xx10^(-5)`

Remember
`color(white)("XXX")log_b a = c` means `b^c = a`
and
`color(white)("XXX")`the default base (`b`) for `log` is `10`