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How do you solve $- log x = 4.176$ $-log x = 4.176$ ?

1 Answer

Dec 7, 2015

$x ≅ 6.668 \times 10^{- 5}$ $x~= 6.668xx10^(-5)$

Explanation:

$- log x = 4.176$ $-log x = 4.176$
$XXX \Rightarrow log x = - 4.176$ $color(white)("XXX") rArr log x = -4.176$

$XXX 10^{- 4.176} = x$ $color(white)("XXX")10^(-4.176) = x$

therefore (using a calculator)
$XXX x = 6.668 \times 10^{- 5}$ $color(white)("XXX")x = 6.668xx10^(-5)$

Remember
$XXX {log}_{b} a = c$ $color(white)("XXX")log_b a = c$ means $b^{c} = a$ $b^c = a$
and
$XXX$ $color(white)("XXX")$ the default base ( $b$ $b$ ) for $log$ $log$ is $10$ $10$

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