If (-1, y) lies on the graph of y = 3^x+1, then what is y?

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Answer 1 · 2015-12-09T06:36:43

it depend on what the original question is
if #y= 3^x + 1# , then solution is #(-1, 4/3)#

If #y= 3^(x+1)# , then solution is #(-1, 1)#

Assuming your question:
If the point #(-1, y)# lies on the graph #y= 3^x + 1# then what is #y#

We are given #x= -1# , and the #y= 3^x +1# ; let substitute #-1# for #x# into the equation

#y= 3^(-1) + 1#
#y = 1/3 + 1#
#y= 1/3 + 3/3#
#y= 4/3#

The point is #(-1, 4/3)#

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Assuming your question is this
If the point #(-1, y)# lies on the graph of #y= 3^(x+1)#, then what is #y#?

Substitute #-1# for #x# into the given equation

#y = 3^(-1+1)#
#y= 3^0#
#y= 1#

The point is #(-1, 1)#