What is the standard form of # y= (2x-9)(x-5)-(2x+7)^2#?

1 Answer
Dec 10, 2015

#y=-2x^2-47x-4#

Explanation:

The general standard form for a quadratic is
#color(white)("XXX")y=ax^2+bx+c#
with constants #a, b, c#

Given
#color(white)("XXX")y=color(red)((2x-9)(x-5))-color(blue)((2x+7)^2)#

Expanding the terms:
#color(white)("XXX")y=color(red)((2x^2-19x+45))-color(blue)((4x^2+28x+49))#

Combine like terms:
#color(white)("XXX")y=-2x^2-47x-4#