What is the standard form of #y=(3x-5)(2x+11)#?

1 Answer
Dec 12, 2015

#y=6x^2+23x-55#

Explanation:

Standard form is #y=ax^2+bx+c#

So you want to multiply the two factors together.
You can use Foil where you multiply the first two terms then the outer, inner, and last terms. Then add them together

#3x*2x=6x#

#3x*11=33x#

#-5*2x=-10x#

#-5*11=-55#

#y=6x^2+33x+(-10x)+(-55)#

Combine like terms

#y=6x^2+23x-55#