Question

How do you differentiate `f(x)=x^2-x-x(x-1)` using the sum rule?

Answer 1

`f'(x)=0 , AAx in RR`

Explanation:

Simplifying function into standard polynomial form by multiplying out the brackets we get

`f(x)=x^2-x-x^2+x`

`therefore f'(x)=2x-1-2x+1`

`=0`