How do you simplify #2sqrt(-16/7)#?

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Answer 1 · 2015-12-13T22:23:27

#(8sqrt7i)/7#

This can be rewritten as

#2sqrt(-1xx16/7)#

#=2isqrt(16/7)#

#=(2isqrt(16))/sqrt7#

#=(8i)/sqrt7#

#=(8i)/sqrt7(sqrt7/sqrt7)#

#=(8sqrt7i)/7#

Notice that the #i# is not included in the square root in the final answer.