Question

How can `(sqrt3,-1)` be converted into polar coordinates?

Answer 1

`2/_-pi/6`

Explanation:

Any complex number in rectangular form `(x,y)=x+iy` may be written in polar form `(r/_theta)` by letting
`r=sqrt(x^2+y^2) and theta = tan^(-1)(y/x)`.

So in this case, `r=sqrt(3+1)=2 and theta = tan^-(1)(-1/sqrt3)=pi/6` and we express it as `-pi/6` since the point is in the 4th quadrant in the argand diagram.