How do you factor completely #x^2+2x+3x+6#?
1 Answer
Dec 16, 2015
Factor by grouping to find:
#x^2+2x+3x+6=(x+3)(x+2)#
Explanation:
Factor by grouping as follows:
#x^2+2x+3x+6#
#=(x^2+2x)+(3x+6)#
#=x(x+2)+3(x+2)#
#=(x+3)(x+2)#
With this question, the hard/fun part has already been done for you, viz splitting the
If you did have to find the split yourself, you would look for two numbers which add up to
Notice that in general,