How do you solve #3x(x - 5) = 7x^2 - 16x#?

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Answer 1 · 2015-12-17T07:26:09

Distribute in the left side and solve the resulting quadratic equation.

3x(x - 5) = #7x^2# - 16x

#3x^2# - 15x = #7x^2# - 16x

0 = #4x^2# - x

You can now solve by factoring:

0 = x(4x - 1)

x = 0 and #1/4#.

Your solution set is x = 0 and x = #1/4#.

Hopefully you understand.