Question

What is the moment of inertia of a pendulum with a mass of `5 kg` that is `5 m` from the pivot?

Answer 1

`125" ""kg.m"^2`

Explanation:

We can consider the mass `m` to be a point mass which is at a distance `r` from the pivot.

The moment of inertia `I` is given by:

`I=mr^2`

`:.I=5xx5^2=125" ""kg.m"^2`