Question

How do you simplify `((n-k)!) /( n!)`?

Answer 1

`((n-k)!)/(n!) = 1/((n-k+1)!)`

Explanation:

You simply develop `n!` and `(n-k)!`. `n-k < n` so `(n-k)! < n!` and `(n-k)!` divides `n!`.

All the terms of `(n-k)!` are included in `n!`, hence the answer.