What is the standard form of #y= (3x-1)(4x-2) #?

1 Answer
Dec 18, 2015

#y=12x^2-10x+2#

Explanation:

The general standard form for a quadratic is:
#color(white)("XXX")y=ax^2+bx+c#

The given equation: #y=(color(red)(3x-1))(color(blue)(4x-2))#
can be transformed into the standard form by multiplying the factors on the right side.

#{: (xx," |",color(red)(3x),color(red)(-1)), ("-----",,"-----","-----"), (color(blue)(4x)," |",12x^2,-4x), (color(blue)(-2)," |",-6x,+2), ("-----","-----","-----","-----"), (,color(green)(12x^2),color(green)(-10x),color(green)(+2)) :}#